KELAS TAMBAHAN

ATTENTION TO ALL YEAR 5 STUDENTS SJK(T) HARVARD 1.

HOMEWORK

1. Print the question paper.
2. Complete the homework.
3. Bring the paper on 19.12.2012 together with your answer.

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M.Sundaramoorthi

KUIZ MATEMATIK (NEW)

9 vd;w vz;iz eP+;fs;  4  Kiw gad;gLj;jyhk;/ mt;thW gad;gLj;jp mikf;Fk; bghGJ Tl;Lj; bjhif 100 MFk;/ fzpj;Jr; brhy;Y+;fs; ghh;g;nghk;////// tpilia mDg;g[+;fs;/

Nombor 9 boleh digunakan sebanyak 4 kali. Apabila digunakan hasil tambahnya akan menjadi 100. Cuba cari jawapan.

Hantar jawapan anda .......

Kuiz Matematik

8 vd;w vz;iz eP+;fs; 8 Kiw gad;gLj;jyhk;/ mt;thW gad;gLj;jp mikf;Fk; bghGJ Tl;Lj; bjhif 1000 MFk;/ fzpj;Jr; brhy;Y+;fs; ghh;g;nghk;////// tpilia mDg;g[+;fs;/

Nombor 8 boleh digunakan sebanyak 8 kali. Apabila digunakan hasil tambahnya akan menjadi 1000. Cuba cari jawapan.

Hantar jawapan anda .......

CUBALAH KUIZ MATEMATIK ( New)

3 vd;w vz;iz eP+;fs;  8  Kiw  gad;gLj;jyhk;/ mt;thW  gad;gLj;jp  mikf;Fk; bghGJ Tl;Lj; bjhif  100  MFk;/  fzpj;Jr; brhy;Y+;fs;  ghh;g;nghk;//////  tpilia mDg;g[+;fs;/

Nombor 3 boleh digunakan sebanyak 8 kali. Apabila digunakan hasil tambahnya akan menjadi 100. Cuba cari jawapan.

Hantar jawapan anda .......

SOALAN RAMALAN UPSR K2

Soalan ini adalah sebagai latihan tambahan sahaja.
Cubalah contoh soalan ini.
Selamat berjaya dalam peperiksaan. GOOD LUCK !

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Soalan Ramalan UPSR

Soalan ini adalah sebagai latihan tambahan sahaja.
Cubalah contoh soalan ini.   ( NEW )

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KERTAS SOALAN PERCUBAAN 2 MATEMATIK SJK (TAMIL) 2012

கெடா மாநில யூ.பி.எஸ்.ஆர் மாதிரி
 மதிப்பீட்டுச் சோதனை 2 ( கணிதம்)

KERTAS 1 / தாள் 1
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KERTAS 2 / தாள் 2

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Whole Number Topical Questions

முழு எண்கள்

Past Year Questions ( 1999 - 2011)

தமிழ் மொழி ஆக்கம்

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KERTAS SOLAN PERCUBAAN (1) SJK TAMIL NEGERI KEDAH 2012

MATEMATIK K1

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MATEMATIK K2

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DECIMAL TOPICAL QUESTION (UPSR)

DECIMAL UPSR PAST YEAR QUESTION

தசம பின்னம் யூ. பி. எஸ்.ஆர் மாதிரி கேள்விகள்

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AREA 2

Example 2

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PERIMETER / சுற்றளவு

EXAMPLE QUESTION / CONTOH SOALAN / மாதிரி கேள்வி


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AREA / பரப்பளவு

Formula

1)  Area  square / Rectangle  = length x breadth

         சதுரம் / செவ்வகம் பரப்பளவு  = நீளம் x அகலம்

2) Area  Triangle  =  length x height    OR   1  x length x height
                                    2                          2
      
       முக்கோணத்தின் பரப்பளவு

   =  நீளம்  x  உயரம்   அல்லது   1  x  நீளம் x உயரம்
                 2                                         2

Example / Contoh / மாதிரி

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FRACTION

Example 1/ Contoh 1/ மாதிரி 1                       Example 2/ Contoh 2/ மாதிரி 2

    1     +    1                                                                       3     -      2    
    2           4                                                                       4             3 

 =   1 x 2    +  1                                                          =   3 x 3    -    2 x 4  
      2 x 2         4                                                               4 x 3         3 x 4            

=   2   +  1                                                                     =    9  -   8
     4       4                                                                          12    12

=  3                                                                                   =   1
    4                                                                                       12
Example 3/ Contoh 3/ மாதிரி 3             Example 4/Contoh 4/மாதிரி 4
                                     
  5   1    -      4                                                4     ÷    8 
       7           7                                                5  

=   5-1     7 + 1      -   4                              =   4     x     1   ( fraction inverted )
                 7              7                                    5            8

=    4   8    -    4                                          =   1  
           7         7                                               10
    
=    4    4
            7
               

WHOLE NUMBERS

EXAMPLES
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CONTOH SOALAN / Examples

1) State the digit value of the digit 2 in the number  82 049.
    82 049 என்ற எண்ணில், இலக்கம் 2 இன் இலக்க மதிப்பைக் குறிப்பிடுக.

        Answer / விடை =  2000

2) State the place value of the digit 5 in the number  43 571.
     43 571 என்ற எண்ணில், இலக்கம் 5 இன் இட மதிப்பைக் குறிப்பிடுக.

       Answer / விடை =  hundreds / நூறு


3) Write " sixty two thousand and seventy three " in numeral.
     " அறுபத்து இரண்டாயிரத்து எழுபத்து மூன்றை" எண்ணால் எழுதுக.

       Answer / விடை =   62 073 

4) Partition / Extented Notation / பிரித்து எழுதுதல்.

        a)   53 456  = 50 000 + 3 000 +  400 + 50 + 6  
                                                                         ( numeral / எண்)

        b)  53 456 = 5 ten thousands + 3 thousands + 4 hundreds + 
                             5 tens + 6 ones                     ( word / எழுத்து) 

Round Off / Nearest

6 250746 =   Nearest ten                          = 6 250750
                     Nearest hundred                 = 6 250700
                     Nearest thousand                = 6 251000
                     Nearest ten thousand          = 6 250000
                     Nearest hundred thousand = 6 300000
                     Nearest million                    = 6 000 000

CONTOH KERTAS SOALAN UPSR

Matematik Kertas 2

Matematik Kertas 1

PROBLEM SOLVING QUESTION

Ramli has 560 stamps. 40 % of them are domestic stamps and the remainder are foreign stamps. How many foreign stamps does Ramli have ?
ரம்லியிடம் 560 தபால் தலைகள் இருந்தன. அவற்றில் 40 % உள்நாட்டுத் தபால் தபால் தலைகளும் எஞ்சியவை வெளிநாட்டுத் தபால் தலைகளும் ஆகும். ரம்லியிடம் உள்ள வெளிநாட்டுத் தபால் தலைகள் எத்தனை ?


 Method 1/ வழிமுறை 1        Method 2/ வழிமுறை 2            

 Step 1 / படி 1                                                             Step 1 / படி 1

=       40  x  560                                  100 % - 40 % = 60 %
     100
=   4 x 56                                          Step 2 / படி 2 
=  224                                        
                                                         =  60   x 560  
Step 2 / படி 2                                                               100
                                                         =  336
560 - 224 =  336

CONVERT UNITS

Example 1                                                                       Example 2

12.8 kg + 3.7 kg = 16.5 kg                      8.5 km -  250 m = 8250 m


     12.8   kg                                                 Convert km to m    
 +    3.7   kg                                                     
     16.5   kg                                              8.5 km x 1000 = 8500 m 

                                                                                                     

                                                                                       8500 m

                                                                                  -      250 m

                                                                                       8250 m 

Example 3

2480 g + 150 g =  2.63 kg

           2480 g                 Convert g to kg

     +      150 g                  2630 g ÷ 1000 = 2.63 kg

           2630 g

MIXED OPERATION

Year 4 ( Example 1)                                           Year 5 ( Example 2)    

Left to right method                             Left to right method

250 + 78 - 35 =  293                             642 ÷ 2 x 3 = 963

     250                                                   642 ÷   2 = 321
 +   78 
    328                                                         321 
 -   35                                                       x     3        
   293                                                                                      963    


UPSR

BODMAS

Example 1                                                 Example 2

103 - 56 ÷ 4 = 89                                            ( 252 + 84 ) ÷ 14 = 24

56 ÷ 4 = 14 ( solve divide first)                       252 + 84 = 336
                                                                                ( solve bracket first)
103 - 14  = 89 ( Then minus )                          336 ÷  14  = 24
                                                                                                             ( Then divide ) 

PERCENTAGE

Example 1                        Example 2                           Example 3

20 % of  240                 30 % of  RM 3600                25 % of 1.5 kg 

=  20  x  240                =   30   x  RM 3600              =  25  x   1500 g
   100                              100                                      100
=  48                             =  RM 1080                          =  375 g

DECIMAL

Decimal (Y4, Y5 and UPSR )

   Example 1                                   Example 2

  12.5 +  3.4 =  15.9                        25 - 8.75 = 16.25

Write in standard written method

    12 . 5                                           25 . 00
 +   3 . 4                                       -    8 . 75
    15 . 9                                           16 . 25 

TIME

Convert Units Of Time

1 hour = 60 minutes                                    Convert 12-hour system to 24-hour system
1 minutes = 60 seconds                      
1 day = 24 hours
1 week =  7 days                                                         07 : 30 p.m.
1 year = 12 months                                             +      12   00         
1 decade = 10 years                                                    19   30 hours
1 century = 10 decades
1 century = 100 years                                 Convert 24-hour system to 12-hour system
1 year = 365 days                                       
                                                                                 20 45 hours
                                                                            -    12 00          
                                                                                  8: 45 p.m.

Techniques Of Problem Solving

Teaching And Learning Strategies

1. Draw a Diagram
2. Finding Facts
3. Using Logic
4. Working Backwords
5. Guessing And Checking
6. Make a table Chart / Systematic
7. Choosing the Operation
8. Identifying Pattens and Sequences

Based on Polya’ Model

• Understanding the problem
• Devising a plan
• Carrying out the plan
• Looking back at the solution
   

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